The set with deleted basepoint associated to $X$ is the set $\smash {X^{-}}$ defined by
Let $\webleft (X,x_{0}\webright )$ be a pointed set.
The set with deleted basepoint associated to $X$ is the set $\smash {X^{-}}$ defined by
Let $\webleft (X,x_{0}\webright )$ be a pointed set.
Functoriality. The assignment $\webleft (X,x_{0}\webright )\mapsto X^{-}$ defines a functor
where:
Action on Objects. For each $X\in \operatorname {\mathrm{Obj}}\webleft (\mathsf{Sets}^{\mathrm{actv}}_{*}\webright )$, we have
where $X^{-}$ is the set of Definition 6.4.2.1.1.
Action on Morphisms. For each morphism $f\colon X\to Y$ of $\mathsf{Sets}^{\mathrm{actv}}_{*}$, the image
of $f$ by $\webleft (-\webright )^{-}$ is the map defined by
for each $x\in X^{-}$.
Adjoint Equivalence. We have an adjoint equivalence of categories
natural in $X\in \operatorname {\mathrm{Obj}}\webleft (\mathsf{Sets}_{*}\webright )$ and $Y\in \operatorname {\mathrm{Obj}}\webleft (\mathsf{Sets}\webright )$, and by isomorphisms
once again natural in $X\in \operatorname {\mathrm{Obj}}\webleft (\mathsf{Sets}_{*}\webright )$ and $Y\in \operatorname {\mathrm{Obj}}\webleft (\mathsf{Sets}\webright )$.
Symmetric Strong Monoidality With Respect to Wedge Sums. The functor of Item 1 has a symmetric strong monoidal structure
being equipped with isomorphisms of pointed sets
natural in $X,Y\in \operatorname {\mathrm{Obj}}\webleft (\mathsf{Sets}\webright )$.
Symmetric Strong Monoidality With Respect to Smash Products. The free pointed set functor of Item 1 has a symmetric strong monoidal structure
being equipped with isomorphisms of pointed sets
natural in $X,Y\in \operatorname {\mathrm{Obj}}\webleft (\mathsf{Sets}\webright )$.
Preservation of Identities. Let $X\in \operatorname {\mathrm{Obj}}\webleft (\mathsf{Sets}\webright )$. We have
for each $x\in X^{-}$, so $\operatorname {\mathrm{id}}^{-}_{X}=\operatorname {\mathrm{id}}_{X^{-}}$.
Preservation of Composition. Given morphisms of pointed sets
we have
for each $x\in X$, so $\webleft (g\circ f\webright )^{-}=g^{-}\circ f^{-}$.
This finishes the proof.
Map I. We define a map
by sending a map $\xi \colon X^{-}\to Y$ to the active morphism of pointed sets
given by
for each $x\in X$, where this morphism is indeed active since $\xi \webleft (x\webright )\in Y=Y^{+}\setminus \left\{ \star _{Y}\right\} $ for all $x\in X^{-}$.
Map II. We define a map
given by sending an active morphism of pointed sets $\xi \colon X\to Y^{+}$ to the map
defined by
for each $x\in X^{-}$, which is indeed well-defined (in that $\xi \webleft (x\webright )\in Y$ for all $x\in X^{-}$) since $\xi $ is active.
Invertibility I. Given a map of sets $\xi \colon X^{-}\to Y$, we have
Therefore we have
Invertibility II. Given a morphism of pointed sets
we have
Therefore we have
Naturality for $\Phi $, Part I. We need to show that, given a morphism of pointed sets
the diagram
Therefore we have
and the naturality diagram for $\Phi $ above indeed commutes.
Naturality for $\Phi $, Part II. We need to show that, given a morphism of pointed sets
the diagram
Therefore we have
and the naturality diagram for $\Phi $ above indeed commutes.
Naturality for $\Psi $. Since $\Phi $ is natural in each argument and $\Phi $ is a componentwise inverse to $\Psi $ in each argument, it follows from Chapter 11: Categories, Item 2 of Proposition 11.9.7.1.2 that $\Psi $ is also natural in each argument.
Fully Faithfulness of $\webleft (-\webright )^{-}$. We aim to show that the assignment $f\mapsto f^{-}$ sets up a bijection
Indeed, the inverse map
is given by sending a map of sets $f\colon X^{-}\to Y^{-}$ to the active morphism of pointed sets $f^{\dagger }\colon X\to Y$ defined by
for each $x\in X$.
Essential Surjectivity of $\webleft (-\webright )^{-}$. We need to show that, given an object $X\in \operatorname {\mathrm{Obj}}\webleft (\mathsf{Sets}\webright )$, there exists some $X'\in \operatorname {\mathrm{Obj}}\webleft (\mathsf{Sets}^{\mathrm{actv}}_{*}\webright )$ such that $\webleft (X'\webright )^{-}\cong X$. Indeed, taking $X'=X^{+}$, we have
and thus we have in fact an equality $\webleft (X^{+}\webright )^{-}=X$, showing $\webleft (-\webright )^{-}$ to be essentially surjective.
The Functor $\webleft (-\webright )^{-}$ Is an Equivalence. Since $\webleft (-\webright )^{-}$ is fully faithful and essentially surjective, it is an equivalence by Chapter 11: Categories, Item 1 of Proposition 11.6.7.1.2.
This finishes the proof.
The Strong Monoidality Constraints. The isomorphism
is given by
for each $z\in X^{-}\mathchoice {\mathbin {\textstyle \coprod }}{\mathbin {\textstyle \coprod }}{\mathbin {\scriptstyle \textstyle \coprod }}{\mathbin {\scriptscriptstyle \textstyle \coprod }}Y^{-}$, with inverse
given by
for each $z\in \webleft (X\vee Y\webright )^{-}$.
The Strong Monoidal Unity Constraint. The isomorphism
is an equality.
The verification that these isomorphisms satisfy the coherence conditions making the functor $\webleft (-\webright )^{-}$ into a symmetric strong monoidal functor is omitted.
The Strong Monoidality Constraints. The isomorphism
is given by
for each $\webleft (x,y\webright )\in X^{-}\times Y^{-}$, with inverse
given by
for each $x\wedge y\in \webleft (X\wedge Y\webright )^{-}$.
The Strong Monoidal Unity Constraint. The isomorphism
is given by sending $\star $ to $1$.
The verification that these isomorphisms satisfy the coherence conditions making the functor $\webleft (-\webright )^{+}$ into a symmetric strong monoidal functor is omitted.