4.7.3 Bijective Functions

Let $A$ and $B$ be sets.

A function $f\colon A\to B$ is bijective if it is injective and surjective.

Let $f\colon A\to B$ be a function.

  1. 1.

    Characterisations. The following conditions are equivalent:

    1. (a)

      The function $f$ is bijective.

    2. (b)

      The function $f$ is an isomorphism in $\mathsf{Sets}$.

    3. (c)

      The function $f$ is a monomorphism and an epimorphism in $\mathsf{Sets}$.

    4. (d)

      We have $f_{!}=f_{*}$.

    5. (e)

      The direct image function

      \[ f_{!}\colon \mathcal{P}(A)\to \mathcal{P}(B) \]

      associated to $f$ is bijective.

    6. (f)

      The inverse image function

      \[ f^{-1}\colon \mathcal{P}(B)\to \mathcal{P}(A) \]

      associated to $f$ is bijective.

    7. (g)

      The codirect image function

      \[ f_{*}\colon \mathcal{P}(A)\to \mathcal{P}(B) \]

      associated to $f$ is bijective.

    8. (h)

      The direct image functor

      \[ f_{!}\colon (\mathcal{P}(A),\subset )\to (\mathcal{P}(B),\subset ) \]

      associated to $f$ is an equivalence of categories.

    9. (i)

      The inverse image functor

      \[ f^{-1}\colon (\mathcal{P}(B),\subset )\to (\mathcal{P}(A),\subset ) \]

      associated to $f$ is an equivalence of categories.

    10. (j)

      The codirect image functor

      \[ f_{*}\colon (\mathcal{P}(A),\subset )\to (\mathcal{P}(B),\subset ) \]

      associated to $f$ is an equivalence of categories.

    11. (k)

      We have

      That is, we have

      \begin{align*} f^{-1}(f(a)) & = \left\{ a\right\} ,\\ f_{!}(f^{-1}(b)) & = \left\{ b\right\} \end{align*}

      for each $a\in A$ and each $b\in B$.

    12. (l)

      We have

    13. (m)

      We have

  2. 2.

    Two-Out-of-Three. Let

    be a diagram in $\mathsf{Sets}$. If two out of the three morphisms among $f$, $g$, and $g\circ f$ are bijections, then so is the third.

Item 1: Characterisations
We proceed by showing:

Step 1: Item 1a$\iff $Item 1b
Omitted.

Step 2: Item 1a$\iff $Item 1c
This follows from Item 1b of Item 1 of Proposition 4.7.1.1.2 and Item 1b of Item 1 of Proposition 4.7.2.1.2.

Step 3: Item 1a$\iff $Item 1d
This follows from Item 19 and Item 20 of Proposition 4.6.3.1.7.

Step 4: Item 1a$\iff $Item 1e
This follows from Item 1b of Item 1 of Proposition 4.7.1.1.2 and Item 1e of Item 1 of Proposition 4.7.2.1.2.

Step 5: Item 1a$\iff $Item 1f
This follows from Item 1e of Item 1 of Proposition 4.7.1.1.2 and Item 1d of Item 1 of Proposition 4.7.2.1.2.

Step 6: Item 1a$\iff $Item 1g
This follows from Item 1f of Item 1 of Proposition 4.7.1.1.2 and Item 1f of Item 1 of Proposition 4.7.2.1.2.

Step 7: Item 1a$\iff $Item 1k
This follows from Item 1l of Item 1 of Proposition 4.7.1.1.2 and Item 1k of Item 1 of Proposition 4.7.2.1.2.

Step 8: Item 1a$\iff $Item 1l
This follows from Item 1m of Item 1 of Proposition 4.7.1.1.2 and Item 1l of Item 1 of Proposition 4.7.2.1.2.

Step 9: Item 1a$\iff $Item 1l
This follows from Item 1n of Item 1 of Proposition 4.7.1.1.2 and Item 1m of Item 1 of Proposition 4.7.2.1.2.

Step 10: Item 1e$\iff $Item 1h
This follows from the fact that $\mathcal{P}(B)$ is locally posetal.

Step 11: Item 1f$\iff $Item 1i
This follows from the fact that $\mathcal{P}(A)$ is locally posetal.

Step 12: Item 1g$\iff $Item 1j
This follows from the fact that $\mathcal{P}(B)$ is locally posetal.

Item 2: Two-Out-of-Three
This is a special case of Chapter 11: Categories, Item 1 of Proposition 11.4.1.1.3.


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