A function $f\colon A\to B$ is bijective if it is injective and surjective.
Let $f\colon A\to B$ be a function.
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1.
Characterisations. The following conditions are equivalent:
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(a)
The function $f$ is bijective.
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(b)
The function $f$ is an isomorphism in $\mathsf{Sets}$.
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(c)
The function $f$ is a monomorphism and an epimorphism in $\mathsf{Sets}$.
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(d)
We have $f_{!}=f_{*}$.
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(e)
The direct image function
\[ f_{!}\colon \mathcal{P}(A)\to \mathcal{P}(B) \]associated to $f$ is bijective.
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(f)
The inverse image function
\[ f^{-1}\colon \mathcal{P}(B)\to \mathcal{P}(A) \]associated to $f$ is bijective.
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(g)
The codirect image function
\[ f_{*}\colon \mathcal{P}(A)\to \mathcal{P}(B) \]associated to $f$ is bijective.
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(h)
The direct image functor
\[ f_{!}\colon (\mathcal{P}(A),\subset )\to (\mathcal{P}(B),\subset ) \]associated to $f$ is an equivalence of categories.
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(i)
The inverse image functor
\[ f^{-1}\colon (\mathcal{P}(B),\subset )\to (\mathcal{P}(A),\subset ) \]associated to $f$ is an equivalence of categories.
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(j)
The codirect image functor
\[ f_{*}\colon (\mathcal{P}(A),\subset )\to (\mathcal{P}(B),\subset ) \]associated to $f$ is an equivalence of categories.
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(k)
We have
That is, we have\begin{align*} f^{-1}(f(a)) & = \left\{ a\right\} ,\\ f_{!}(f^{-1}(b)) & = \left\{ b\right\} \end{align*}for each $a\in A$ and each $b\in B$.
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(l)
We have
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(m)
We have
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(a)
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2.
Two-Out-of-Three. Let
be a diagram in $\mathsf{Sets}$. If two out of the three morphisms among $f$, $g$, and $g\circ f$ are bijections, then so is the third.
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Omitted.
This follows from Item 1b of Item 1 of Proposition 4.7.1.1.2 and Item 1b of Item 1 of Proposition 4.7.2.1.2.
This follows from Item 19 and Item 20 of Proposition 4.6.3.1.7.
This follows from Item 1b of Item 1 of Proposition 4.7.1.1.2 and Item 1e of Item 1 of Proposition 4.7.2.1.2.
This follows from Item 1e of Item 1 of Proposition 4.7.1.1.2 and Item 1d of Item 1 of Proposition 4.7.2.1.2.
This follows from Item 1f of Item 1 of Proposition 4.7.1.1.2 and Item 1f of Item 1 of Proposition 4.7.2.1.2.
This follows from Item 1l of Item 1 of Proposition 4.7.1.1.2 and Item 1k of Item 1 of Proposition 4.7.2.1.2.
This follows from Item 1m of Item 1 of Proposition 4.7.1.1.2 and Item 1l of Item 1 of Proposition 4.7.2.1.2.
This follows from Item 1n of Item 1 of Proposition 4.7.1.1.2 and Item 1m of Item 1 of Proposition 4.7.2.1.2.
This follows from the fact that $\mathcal{P}(B)$ is locally posetal.
This follows from the fact that $\mathcal{P}(A)$ is locally posetal.
This follows from the fact that $\mathcal{P}(B)$ is locally posetal.