8.4.1 Self-Duality

    The ($2$-)category of relations is self-dual:

    1. 1.

      Self-Duality I. We have an isomorphism

      \[ \mathrm{Rel}^{\mathsf{op}}\mathrel {\smash {\overset {\scriptscriptstyle \text{eq.}}\cong }}\mathrm{Rel} \]

      of categories.

  • 2.

    Self-Duality II. We have a $2$-isomorphism

    \[ \boldsymbol {\mathsf{Rel}}^{\mathsf{op}}\mathrel {\smash {\overset {\scriptscriptstyle \text{eq.}}\cong }}\boldsymbol {\mathsf{Rel}} \]

    of $2$-categories.

  • Item 1: Self-Duality I
    We claim that the functor

    \[ F\colon \mathsf{Rel}^{\mathsf{op}}\to \mathsf{Rel} \]

    given by the identity on objects and by $R\mapsto R^{\dagger }$ on morphisms is an isomorphism of categories.

    By Chapter 11: Categories, Item 1 of Proposition 11.6.8.1.3, it suffices to show that $F$ is bijective on objects (which is clear) and fully faithful. Indeed, the map

    \[ \webleft (-\webright )^{\dagger }\colon \mathrm{Rel}\webleft (A,B\webright )\to \mathrm{Rel}\webleft (B,A\webright ) \]

    defined by the assignment $R\mapsto R^{\dagger }$ is a bijection by Chapter 9: Constructions With Relations, Unresolved reference of Unresolved reference, showing $F$ to be fully faithful.

    Item 2: Self-Duality II
    We claim that the $2$-functor

    \[ F\colon \mathsf{Rel}^{\mathsf{op}}\to \mathsf{Rel} \]

    given by the identity on objects, by $R\mapsto R^{\dagger }$ on morphisms, and by preserving inclusions on $2$-morphisms via Chapter 9: Constructions With Relations, Unresolved reference of Unresolved reference, is an isomorphism of categories.

    By Unresolved reference, Unresolved reference of Unresolved reference, it suffices to show that $F$ is:

    Thus $F$ is indeed a $2$-isomorphism of categories.


Noticed something off, or have any comments? Feel free to reach out!


You can also use the contact form below: