The internal Hom of $\mathcal{P}(X)$ from $U$ to $V$ is the subset $[U,V]_{X}$1 of $X$ given by
where $U^{\textsf{c}}$ is the complement of $U$ of Definition 4.3.11.1.1.
- 1Further Notation: Also written $\mathbf{Hom}_{\mathcal{P}(X)}(U,V)$.
Let $X$ be a set and let $U,V\in \mathcal{P}(X)$.
The internal Hom of $\mathcal{P}(X)$ from $U$ to $V$ is the subset $[U,V]_{X}$1 of $X$ given by
where $U^{\textsf{c}}$ is the complement of $U$ of Definition 4.3.11.1.1.
where we have used:
Item 10 of Proposition 4.3.10.1.2 for the second equality.
Item 4 of Proposition 4.3.9.1.2 for the third equality.
Item 4 of Proposition 4.3.8.1.2 for the last equality.
This finishes the proof.
Henning Makholm suggests the following heuristic intuition for the internal Hom of $\mathcal{P}(X)$ from $U$ to $V$ ([B., Show that the powerset partial order is a cartesian closed category]):
Since products in $\mathcal{P}(X)$ are given by binary intersections (Item 1 of Proposition 4.4.1.1.4), the right adjoint $\mathbf{Hom}_{\mathcal{P}(X)}(U,-)$ of $U\cap -$ may be thought of as a function type $[U,V]$.
Under the Curry–Howard correspondence (), the function type $[U,V]$ corresponds to implication $U\Rightarrow V$.
Implication $U\Rightarrow V$ is logically equivalent to $\neg U\vee V$.
The expression $\neg U\vee V$ then corresponds to the set $U^{\textsf{c}}\cup V$ in $\mathcal{P}(X)$.
The set $U^{\textsf{c}}\vee V$ turns out to indeed be the internal Hom of $\mathcal{P}(X)$.
Let $X$ be a set.
Functoriality. The assignments $U,V,(U,V)\mapsto \mathbf{Hom}_{\mathcal{P}(X)}$ define functors
In particular, the following statements hold for each $U,V,A,B\in \mathcal{P}(X)$:
Adjointness. We have adjunctions
In particular, the following statements hold for each $U,V,W\in \mathcal{P}(X)$:
Interaction With the Empty Set I. We have
natural in $U,V\in \mathcal{P}(X)$.
Interaction With $X$. We have
natural in $U,V\in \mathcal{P}(X)$.
Interaction With the Empty Set II. The functor
defined by
is an involutory isomorphism of categories, making $\text{Ø}$ into a dualising object for $(\mathcal{P}(X),\cap ,X,[-,-]_{X})$ in the sense of . In particular:
The diagram
for each $U\in \mathcal{P}(X)$.
The diagram
for each $U,V\in \mathcal{P}(X)$.
Interaction With the Empty Set III. Let $f\colon X\to Y$ be a function.
Interaction With Direct Images. The diagram
for each $U\in \mathcal{P}(X)$.
Interaction With Inverse Images. The diagram
for each $U\in \mathcal{P}(X)$.
Interaction With Codirect Images. The diagram
for each $U\in \mathcal{P}(X)$.
Interaction With Unions of Families of Subsets I. The diagram
in general, where $\mathcal{U}\in \mathcal{P}(\mathcal{P}(X))$.
Interaction With Unions of Families of Subsets II. The diagram
for each $\mathcal{U}\in \mathcal{P}(\mathcal{P}(X))$ and each $V\in \mathcal{P}(X)$.
Interaction With Unions of Families of Subsets III. The diagram
for each $U\in \mathcal{P}(X)$ and each $\mathcal{V}\in \mathcal{P}(\mathcal{P}(X))$.
Interaction With Intersections of Families of Subsets I. The diagram
in general, where $\mathcal{U}\in \mathcal{P}(\mathcal{P}(X))$.
Interaction With Intersections of Families of Subsets II. The diagram
for each $\mathcal{U}\in \mathcal{P}(\mathcal{P}(X))$ and each $V\in \mathcal{P}(X)$.
Interaction With Intersections of Families of Subsets III. The diagram
for each $U\in \mathcal{P}(X)$ and each $\mathcal{V}\in \mathcal{P}(\mathcal{P}(X))$.
Interaction With Binary Unions. We have equalities of sets
for each $U,V,W\in \mathcal{P}(X)$.
Interaction With Binary Intersections. We have equalities of sets
for each $U,V,W\in \mathcal{P}(X)$.
Interaction With Differences. We have equalities of sets
for each $U,V,W\in \mathcal{P}(X)$.
Interaction With Complements. We have equalities of sets
for each $U,V\in \mathcal{P}(X)$.
Interaction With Characteristic Functions. We have
for each $U,V\in \mathcal{P}(X)$.
Interaction With Direct Images. Let $f\colon X\to Y$ be a function. The diagram
natural in $U,V\in \mathcal{P}(X)$.
Interaction With Inverse Images. Let $f\colon X\to Y$ be a function. The diagram
natural in $U,V\in \mathcal{P}(X)$.
Interaction With Codirect Images. Let $f\colon X\to Y$ be a function. We have a natural transformation
indexed by $U,V\in \mathcal{P}(X)$.
Proof of Item 1a: We have
where we have used:
Item 1 of Proposition 4.3.11.1.2, which states that if $U\subset A$, then $A^{\textsf{c}}\subset U^{\textsf{c}}$.
Item 1a of Item 1 of Proposition 4.3.11.1.2, which states that if $A^{\textsf{c}}\subset U^{\textsf{c}}$, then $A^{\textsf{c}}\cup K\subset U^{\textsf{c}}\cup K$ for any $K\in \mathcal{P}(X)$.
Proof of Item 1b: We have
where we have used Item 1b of Item 1 of Proposition 4.3.11.1.2, which states that if $V\subset B$, then $K\cup V\subset K\cup B$ for any $K\in \mathcal{P}(X)$.
Proof of Item 1c: We have
This finishes the proof.
where we have used Item 3 of Proposition 4.3.8.1.2, and we have
where we have used:
Item 12 of Proposition 4.3.10.1.2 for the first equality.
Item 5 of Proposition 4.3.8.1.2 for the last equality.
Since $\mathcal{P}(X)$ is posetal, naturality is automatic (Chapter 11: Categories, Item 4 of Proposition 11.2.7.1.2).
where we have used Item 5 of Proposition 4.3.8.1.2, and we have
where we have used Item 3 of Proposition 4.3.8.1.2 for the last equality. Since $\mathcal{P}(X)$ is posetal, naturality is automatic (Chapter 11: Categories, Item 4 of Proposition 11.2.7.1.2).
where we have used:
Item 3 for the second and third equalities.
Item 3 of Proposition 4.3.11.1.2 for the fourth equality.
Since $\mathcal{P}(X)$ is posetal, naturality is automatic (Chapter 11: Categories, Item 4 of Proposition 11.2.7.1.2), and thus we have
This finishes the proof.
With this, the counterexample given in the proof of Item 10 of Proposition 4.3.6.1.2 then applies.
where we have used:
Item 11 of Proposition 4.3.6.1.2 for the second equality.
Item 6 of Proposition 4.3.7.1.2 for the third equality.
This finishes the proof.
where we have used Item 6. This finishes the proof.
whereas
Thus we have
This finishes the proof.
where we have used:
Item 12 of Proposition 4.3.6.1.2 for the second equality.
Item 6 of Proposition 4.3.7.1.2 for the third equality.
This finishes the proof.
where we have used Item 6. This finishes the proof.
where we have used:
Item 2 of Proposition 4.3.11.1.2 for the second equality.
Item 8 of Proposition 4.3.8.1.2 for the third equality.
Several applications of Item 2 and Item 4 of Proposition 4.3.8.1.2 and for the fourth equality.
For the second equality in the statement, we have
where we have used Item 6 of Proposition 4.3.8.1.2 for the second equality.
where we have used:
Item 2 of Proposition 4.3.11.1.2 for the second equality.
Item 6 of Proposition 4.3.8.1.2 for the third equality.
Now, for the second equality in the statement, we have
where we have used:
Item 8 of Proposition 4.3.8.1.2 for the second equality.
Several applications of Item 2 and Item 4 of Proposition 4.3.8.1.2 and for the third equality.
This finishes the proof.
where we have used:
Item 10 of Proposition 4.3.10.1.2 for the third equality.
Item 4 of Proposition 4.3.9.1.2 for the fourth equality.
Item 8 of Proposition 4.3.8.1.2 for the sixth equality.
Several applications of Item 2 and Item 4 of Proposition 4.3.8.1.2 and for the seventh equality.
We also have
where we have used:
Item 10 of Proposition 4.3.10.1.2 for the third equality.
Item 4 of Proposition 4.3.9.1.2 for the fourth equality.
Item 8 of Proposition 4.3.8.1.2 for the sixth equality.
Several applications of Item 2 and Item 4 of Proposition 4.3.8.1.2 and for the seventh equality.
Item 3 of Proposition 4.3.11.1.2 for the eighth equality.
Now, for the second equality in the statement, we have
where we have used:
Item 4 of Proposition 4.3.8.1.2 for the second equality.
Item 4 of Proposition 4.3.10.1.2 for the third equality.
Item 10 of Proposition 4.3.10.1.2 for the fifth equality.
Item 13 of Proposition 4.3.10.1.2 for the sixth equality.
Item 3 of Proposition 4.3.8.1.2 for the seventh equality.
Item 5 of Proposition 4.3.9.1.2 for the eighth equality.
This finishes the proof.
where we have used Item 3 of Proposition 4.3.11.1.2. We also have
where we have used Item 2 of Proposition 4.3.11.1.2. Finally, we have
where we have used Item 2 of Proposition 4.3.11.1.2.
where we have used:
Item 10 of Proposition 4.3.8.1.2 for the second equality.
Item 4 of Proposition 4.3.11.1.2 for the third equality.
This finishes the proof.